全概率证明彩票
设A1={第一个人获得电影票}
A2={第一个人没拿到电影票}
B={第二个人拿到电影票}
P(A1)=6/10
P(A2)=4/10
P(B|A1)=5/9
P(B|A2)=6/9
P(B)= P(a 1)P(B | a 1)+P(a 1)P(B | a 1)
=6/10 5/9+4/10 6/9
=54/90
=3/5
A2={第一个人没拿到电影票}
B={第二个人拿到电影票}
P(A1)=6/10
P(A2)=4/10
P(B|A1)=5/9
P(B|A2)=6/9
P(B)= P(a 1)P(B | a 1)+P(a 1)P(B | a 1)
=6/10 5/9+4/10 6/9
=54/90
=3/5